Hyperbolic Functions
Hyperbolic functions are analogs of trigonometric functions defined using exponential functions. They have applications in physics, engineering, and calculus.
Definitions
Hyperbolic functions arise from the even/odd decomposition of the exponential function $e^x$:
$$e^x = \underbrace{\frac{e^x + e^{-x}}{2}}{\text{even}} + \underbrace{\frac{e^x - e^{-x}}{2}}{\text{odd}}$$
Hyperbolic Sine
$$\sinh x = \frac{e^x - e^{-x}}{2} = \frac{1}{2}e^x - \frac{1}{2}e^{-x}$$
- Domain: $(-\infty, \infty)$
- Range: $(-\infty, \infty)$
- Parity: Odd ($\sinh(-x) = -\sinh x$)
Hyperbolic Cosine
$$\cosh x = \frac{e^x + e^{-x}}{2} = \frac{1}{2}e^x + \frac{1}{2}e^{-x}$$
- Domain: $(-\infty, \infty)$
- Range: $[1, \infty)$
- Parity: Even ($\cosh(-x) = \cosh x$)
Hyperbolic Tangent
$$\tanh x = \frac{\sinh x}{\cosh x} = \frac{e^x - e^{-x}}{e^x + e^{-x}}$$
- Domain: $(-\infty, \infty)$
- Range: $(-1, 1)$
- Parity: Odd
- Asymptotes: Horizontal asymptotes $y = -1$ and $y = 1$
Other Hyperbolic Functions
- $\coth x = \frac{\cosh x}{\sinh x} = \frac{e^x + e^{-x}}{e^x - e^{-x}}$
- $\operatorname{sech} x = \frac{1}{\cosh x} = \frac{2}{e^x + e^{-x}}$
- $\operatorname{cosech} x = \frac{1}{\sinh x} = \frac{2}{e^x - e^{-x}}$
Note: $\operatorname{cosech} x$ is also commonly written as $\operatorname{csch} x$.
Hyperbolic vs Trigonometric Comparison
flowchart LR
subgraph Trig["Trigonometric"]
direction TB
T1["sin x"]
T2["cos x"]
T3["tan x"]
T4["csc x"]
T5["sec x"]
T6["cot x"]
TI["Identity: sin²x + cos²x = 1"]
end
subgraph Hyper["Hyperbolic"]
direction TB
H1["sinh x"]
H2["cosh x"]
H3["tanh x"]
H4["csch x"]
H5["sech x"]
H6["coth x"]
HI["Identity: cosh²x - sinh²x = 1"]
end
T1 -.->|Analog| H1
T2 -.->|Analog| H2
T3 -.->|Analog| H3
T4 -.->|Analog| H4
T5 -.->|Analog| H5
T6 -.->|Analog| H6
TI -.->|Sign Change| HI
Fundamental Identity
$$\cosh^2 x - \sinh^2 x = 1$$
Compare to: $\cos^2 x + \sin^2 x = 1$
Key Identities
- $\sinh(-x) = -\sinh x$ (odd function)
- $\cosh(-x) = \cosh x$ (even function)
- $\cosh x + \sinh x = e^x$
- $\cosh x - \sinh x = e^{-x}$
- $1 - \tanh^2 x = \text{sech}^2 x$
- $\coth^2 x - 1 = \text{csch}^2 x$
Hyperbolic Identities Flowchart
flowchart TD
A["Fundamental: cosh²x - sinh²x = 1"] --> B["Divide by cosh²x"]
A --> C["Divide by sinh²x"]
B --> D["1 - tanh²x = sech²x"]
C --> E["coth²x - 1 = csch²x"]
A --> F["Addition Formulas"]
F --> G["sinh(x±y) = sinh x cosh y ± cosh x sinh y"]
F --> H["cosh(x±y) = cosh x cosh y ± sinh x sinh y"]
F --> I["tanh(x±y) = (tanh x ± tanh y)/(1 ± tanh x tanh y)"]
A --> J["Double Angle"]
J --> K["sinh 2x = 2 sinh x cosh x"]
J --> L["cosh 2x = cosh²x + sinh²x = 2cosh²x - 1 = 2sinh²x + 1"]
A --> M["Half-Angle"]
M --> N["cosh²x = (cosh 2x + 1)/2"]
M --> O["sinh²x = (cosh 2x - 1)/2"]
Addition Formulas
- $\sinh(x \pm y) = \sinh x \cosh y \pm \cosh x \sinh y$
- $\cosh(x \pm y) = \cosh x \cosh y \pm \sinh x \sinh y$
- $\tanh(x \pm y) = \frac{\tanh x \pm \tanh y}{1 \pm \tanh x \tanh y}$
Double Angle Formulas
- $\sinh(2x) = 2\sinh x \cosh x$
- $\cosh(2x) = \cosh^2 x + \sinh^2 x = 2\cosh^2 x - 1 = 2\sinh^2 x + 1$
Half-Angle (Power-Reduction) Formulas
- $\cosh^2 x = \dfrac{\cosh 2x + 1}{2}$
- $\sinh^2 x = \dfrac{\cosh 2x - 1}{2}$
Derivatives
Basic Derivatives
- $\frac{d}{dx}\sinh x = \cosh x$
- $\frac{d}{dx}\cosh x = \sinh x$
- $\frac{d}{dx}\tanh x = \text{sech}^2 x$
- $\frac{d}{dx}\coth x = -\text{csch}^2 x$
- $\frac{d}{dx}\text{sech } x = -\text{sech } x \tanh x$
- $\frac{d}{dx}\text{csch } x = -\text{csch } x \coth x$
Chain Rule Forms
If $u$ is a differentiable function of $x$:
- $\frac{d}{dx}\sinh u = \cosh u \cdot \frac{du}{dx}$
- $\frac{d}{dx}\cosh u = \sinh u \cdot \frac{du}{dx}$
- $\frac{d}{dx}\tanh u = \text{sech}^2 u \cdot \frac{du}{dx}$
- $\frac{d}{dx}\coth u = -\text{csch}^2 u \cdot \frac{du}{dx}$
- $\frac{d}{dx}\text{sech } u = -\text{sech } u \tanh u \cdot \frac{du}{dx}$
- $\frac{d}{dx}\text{csch } u = -\text{csch } u \coth u \cdot \frac{du}{dx}$
Integrals
Basic Integrals
- $\int \sinh x , dx = \cosh x + C$
- $\int \cosh x , dx = \sinh x + C$
- $\int \text{sech}^2 x , dx = \tanh x + C$
- $\int \text{csch}^2 x , dx = -\coth x + C$
- $\int \text{sech } x \tanh x , dx = -\text{sech } x + C$
- $\int \text{csch } x \coth x , dx = -\text{csch } x + C$
General Forms
- $\int \sinh u , du = \cosh u + C$
- $\int \cosh u , du = \sinh u + C$
- $\int \text{sech}^2 u , du = \tanh u + C$
- $\int \text{csch}^2 u , du = -\coth u + C$
- $\int \text{sech } u \tanh u , du = -\text{sech } u + C$
- $\int \text{csch } u \coth u , du = -\text{csch } u + C$
Common Hyperbolic Integrals by Substitution
- $\int \tanh x , dx = \ln(\cosh x) + C$
(Let $u = \cosh x$, $du = \sinh x , dx$)
Inverse Hyperbolic Functions
Definitions and Domain/Range
Inverse hyperbolic functions are established by reflecting the graphs of hyperbolic functions (with appropriate restrictions) about the line $y = x$.
| Function | Definition | Domain | Range |
|---|---|---|---|
| $\sinh^{-1} x$ | Inverse of $\sinh x$ | $(-\infty, \infty)$ | $(-\infty, \infty)$ |
| $\cosh^{-1} x$ | Inverse of $\cosh x$ (principal branch) | $(1, \infty)$ | $[0, \infty)$ |
| $\tanh^{-1} x$ | Inverse of $\tanh x$ | $(-1, 1)$ | $(-\infty, \infty)$ |
| $\coth^{-1} x$ | Inverse of $\coth x$ | $(-\infty, -1) \cup (1, \infty)$ | $(-\infty, 0) \cup (0, \infty)$ |
| $\text{sech}^{-1} x$ | Inverse of $\text{sech } x$ (principal branch) | $(0, 1)$ | $[0, \infty)$ |
| $\text{csch}^{-1} x$ | Inverse of $\text{csch } x$ | $(-\infty, 0) \cup (0, \infty)$ | $(-\infty, 0) \cup (0, \infty)$ |
Note: For $\cosh^{-1} x$ and $\text{sech}^{-1} x$, the restriction $x \geq 0$ on the original function selects the principal branch, making the function invertible.
Logarithmic Forms
All inverse hyperbolic functions can be expressed using natural logarithms:
$$\sinh^{-1} x = \ln(x + \sqrt{x^2 + 1})$$
$$\cosh^{-1} x = \ln(x + \sqrt{x^2 - 1})$$
$$\tanh^{-1} x = \frac{1}{2}\ln\left(\frac{1+x}{1-x}\right)$$
$$\coth^{-1} x = \frac{1}{2}\ln\left(\frac{x+1}{x-1}\right)$$
$$\text{sech}^{-1} x = \ln\left(\frac{1 + \sqrt{1-x^2}}{x}\right)$$
$$\text{csch}^{-1} x = \ln\left(\frac{1}{x} + \frac{\sqrt{1+x^2}}{|x|}\right)$$
Derivatives
| $f(x)$ | $\frac{d}{dx}f(x)$ | Domain |
|---|---|---|
| $\sinh^{-1} x$ | $\dfrac{1}{\sqrt{1+x^2}}$ | all $x$ |
| $\cosh^{-1} x$ | $\dfrac{1}{\sqrt{x^2-1}}$ | $x > 1$ |
| $\tanh^{-1} x$ | $\dfrac{1}{1-x^2}$ | $ |
| $\coth^{-1} x$ | $\dfrac{1}{1-x^2}$ | $ |
| $\text{sech}^{-1} x$ | $\dfrac{-1}{x\sqrt{1-x^2}}$ | $0 < x < 1$ |
| $\text{csch}^{-1} x$ | $\dfrac{-1}{ | x |
Note: $\frac{d}{dx}\tanh^{-1} x$ and $\frac{d}{dx}\coth^{-1} x$ have the same formula but apply on different domains.
Integrals Leading to Inverse Hyperbolic Functions
The following standard forms produce inverse hyperbolic results. They are often reached after a preliminary $u$-substitution.
-
Inverse sine hyperbolic form: $$\int \frac{dx}{\sqrt{a^2+x^2}} = \sinh^{-1}\left(\frac{x}{a}\right) + C = \ln\left|x + \sqrt{a^2+x^2}\right| + D$$
-
Inverse cosine hyperbolic form: $$\int \frac{dx}{\sqrt{x^2-a^2}} = \cosh^{-1}\left(\frac{x}{a}\right) + C$$
-
Inverse tangent/cotangent hyperbolic form (piecewise): $$\int \frac{dx}{a^2-x^2} = \begin{cases} \displaystyle\frac{1}{a}\tanh^{-1}\left(\frac{x}{a}\right) + C, & |x| < a \ \displaystyle\frac{1}{a}\coth^{-1}\left(\frac{x}{a}\right) + C, & |x| > a \end{cases}$$
-
Inverse cosecant hyperbolic form: $$\int \frac{dx}{x\sqrt{a^2+x^2}} = -\frac{1}{a}\operatorname{csch}^{-1}\left(\frac{x}{a}\right) + C$$
-
Inverse secant hyperbolic form: $$\int \frac{dx}{x\sqrt{a^2-x^2}} = -\frac{1}{a}\operatorname{sech}^{-1}\left(\frac{x}{a}\right) + C$$
Integration Techniques
$u$-Substitution with Hyperbolic Functions
When one factor is the derivative of another hyperbolic term, substitute:
- $u = \sinh x$ when $\cosh x , dx$ is present
- $u = \cosh x$ when $\sinh x , dx$ is present
- $u = \tanh x$ when $\operatorname{sech}^2 x , dx$ is present
- $u = \coth x$ when $\operatorname{csch}^2 x , dx$ is present
Trigonometric vs. Hyperbolic Substitution
For radical forms, either substitution works, but hyperbolic substitution often yields the inverse hyperbolic form directly:
| Form | Trig Substitution | Hyperbolic Substitution |
|---|---|---|
| $\sqrt{a^2+x^2}$ | $x = a\tan\theta$ | $x = a\sinh u$ |
| $\sqrt{x^2-a^2}$ | $x = a\sec\theta$ | $x = a\cosh u$ |
Example — $\displaystyle\int \frac{dx}{\sqrt{a^2+x^2}}$
- With $x = a\sinh u$: $\displaystyle\int du = u + C = \sinh^{-1}!\left(\frac{x}{a}\right) + C$
- With $x = a\tan\theta$: reduces to $\ln\bigl|x + \sqrt{a^2+x^2}\bigr| + D$
Both answers are equivalent because $\sinh^{-1}(x/a) = \ln\bigl|x + \sqrt{a^2+x^2}\bigr| - \ln a$.
Related
- FAC1001 - Advanced Mathematics II — Science stream course
- FAC1004 - Advanced Mathematics II (Computing) — Computing stream course
- FAC1004 L17 — Hyperbolic Functions — introduction lecture
- FAC1004 L18 — Hyperbolic Functions (Derivatives & Integrals) — derivatives lecture
- FAC1004 L19-L20 — Inverse Hyperbolic Functions — inverse functions lecture
- FAC1004 L21-L22 — Integrals Involving Hyperbolic Functions — integrals lecture
- FAC1004 Tutorial 8 — Hyperbolic Functions — practice problems
- FAC1004 Tutorial 9 — Inverse Hyperbolic Functions — inverse functions practice
- FAC1004 Tutorial 10 — Integration of Hyperbolic Functions — integration practice